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JEE Main 2025: What is Difference Between NTA Score and Percentile
Out of the 13,11,544 candidates registering for JEE Main 2025 paper 1 exam, as many as 12,58,136 (95.93 per cent) candidates appeared.

Students are now confused about the difference between NTA score and percentile.
The National Testing Agency (NTA) has announced the Joint Entrance Examination (JEE) Main 2025 Session 1 results today. Candidates can check their results through the official website -- jeemain.nta.nic.in.
Out of the 13,11,544 candidates registering for JEE Main 2025 paper 1 exam, as many as 12,58,136 (95.93 per cent) candidates appeared.
Students are now, however, confused about the difference between NTA score and percentile.
NTA Scores are normalized scores across multi-session papers and are based on the relative performance of all those who appeared for the examination in one session. The marks obtained are converted into a scale ranging from 100 to 0 for each session of examinees. NTA score is not the same as the percentage of marks obtained.
The NTA Score of a Candidate has been calculated as follows:
100 X Number of candidates appeared in the 'Session' with raw score EQUAL TO OR LESS than the candidate
Total number of candidates who appeared in the 'Session'
After both Sessions of the JEE (Main) - 2025 Examination for Paper 1, the rank of the candidates will be released taking into consideration the best of the two NTA Scores in accordance with the policy already made.
For each subject for which the examination is held in multiple shifts, the raw score for each candidate appearing for the subject will be converted into NTA Score (Percentile Score & Normalized Score) in the following three steps.
Step1: Convert Raw Scores into Percentile Scores.
The percentiles are calculated separately for each shift.
1. Record the number of candidates who have appeared in a shift. Denote this number by N.
2. Sort all the candidates in one shift in decreasing order of their marks.
3. Note the raw marks for each candidate. Suppose this is denoted by T. Count the number of candidates in that shift whose raw scores are less than or equal to T. Denote this number by m.
4. The percentile score for this candidate is then calculated as:
P =𝑚/𝑁∗ 100
Step2: Pull-back of the percentiles to the marks scale for each session to get Normalised Score.
• The data across all sessions tabulated at the end of step 1 is collated into a single table.
• The columns for the shift-wise raw score should are kept separate.
• All the records are then sorted in decreasing order of the percentiles.
Step3: Calculation of the Normalised Score
Now for each subject there is a score assigned to each percentile value for each session. The Normalised score, Z, corresponding to a percentile value P, is calculated as
Z= Average of (𝑢𝐴, 𝑢𝐵, 𝑢𝐶, … … … . . 𝑢𝑡)= 𝑢𝐴 + 𝑢𝐵 + 𝑢𝐶 +,…..+ 𝑢t/t
Where 𝑢𝐴, 𝑢𝐵, 𝑢𝐶, … … … . . 𝑢𝑡 denote the raw scores corresponding to the percentile P in each of different sessions
NTA follows this process for all exams that are conducted in multiple shifts, such as JEE Main, CUET UG, CUET PG and others.
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